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-4=4x^2+5x-6
We move all terms to the left:
-4-(4x^2+5x-6)=0
We get rid of parentheses
-4x^2-5x+6-4=0
We add all the numbers together, and all the variables
-4x^2-5x+2=0
a = -4; b = -5; c = +2;
Δ = b2-4ac
Δ = -52-4·(-4)·2
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{57}}{2*-4}=\frac{5-\sqrt{57}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{57}}{2*-4}=\frac{5+\sqrt{57}}{-8} $
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